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If you install special sound-reflecting windows that reduce the sound intensity level by 35.0 dB , by what factor have you reduced the sound intensity

1 Answer

4 votes

Answer:

5000

Step-by-step explanation:

Sound intensity is the power carried by the sound wave per unit area. Its unit is W/m². Commonly this intensity is measured on a logarithmic scale known as 'decibel scale'. On the decibel scale, 0 dB is the threshold of hearing. This corresponds to the sound intensity of
1* 10^(-12) W/m². For a 10 times increase in the sound intensity decibel value increase by 10. That means,

10 dB =
1* 10^(-11) W/m²

By this logic for a reduction in the sound intensity level by 35dB, the sound intensity will be reduced by a factor of 5000.

User Sachin
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