Question

A current of 7.79 A in a solenoid of length 10.6 cm creates a 0.201 T magnetic field at the center of the solenoid. How many turns does this solenoid contain? turns :

Answer 1

Therefore,

2178 number of turns are there in Solenoid.

Step-by-step explanation:

Given:

Current, I = 7.79 A

Length of Solenoid,

`L =10.6\ cm=(10.6)/(100)=0.106\ meter`

magnetic field at the center of the solenoid,

B = 0.201 Tesla

To Find:

N = ? turns

Solution:

Magnetic field at the center of the solenoid is given as,

`B=(\mu_(0)* N* I)/(L)`

Where,

B = Magnetic Field,

N = Number of turns,

I = Current,

L = Length of Solenoid

`\mu_(0)=permeability\ of\ free\ space=4\pi* 10^(-7)\ H/m`

Substituting the values we get

`N=(B* L)/(\mu_(0)* I)`

`N=\dgrac{0.201* 0.106}{4\pi* 10^(-7)* 7.79}=2177.58`

`N\approx 2178\ turns`

Therefore,

2178 number of turns are there in Solenoid.