Question

Lead iodide is virtually insoluble in water so that the reaction appears to go to completion. How many milliliters of 3.550 M HI(aq) must be added to a solution containing 0.700 mol of to completely precipitate the lead?

Answer 1

Step-by-step explanation:

Below is an attachment containing the solution.

Answer 2

394mL

Step-by-step explanation:

the molecular equation is

Pb(NO3)2 + 2 HI = PbI2 + 2 HNO3

the ratio between Pb(NO3)2 and HI is 1 : 2

moles HI required = 0.700 x 2 = 1.40

volume HI = 1.40 mol / 3.550 mol/L=0.394 L = 394 mL