Question

A bat hits a moving baseball. If the bat delivers a net eastward impulse of 1.3 N-s and the ball starts with an initial horizontal velocity of 3.8 m/s to the west and leaves with a 5.4 m/s velocity to the east, what is the mass of the ball (in grams)?

Answer 1

`141.30grams`

Step-by-step explanation:

First, denote our known values;

`J=1.3N-s(+,east)\\u=-3.8ms^-^1(-,west)\\v=5.4ms^-^1(+,east)\\m=?`

Mass is impulse divided by change in velocity:

`m=(J)/(v-u)\\=(1.3)/(5.4--3.8)\\\\=(1.3)/(9.2)\\=0.1413Kgs`

Hence, the mass of the ball is 141.30grams