Question

An experiment requires 0.52 M NH3(aq). The stockroom manager estimates that 15 L of the base is needed. What volume of 15 M NH3(aq) will be used to prepare this amount of 0.52 M base

Answer 1

Answer: 0.52 L of 15 M
`NH_3(aq)` will be used to prepare this amount of 0.52 M base.

Step-by-step explanation:

But on diluting the number of moles remain same and thus we can use molarity equation.

`C_1V_1(stock)=C_2V_2` (to be prepared)

where,

`C_1` =concentration of stock solution = 15 M

`V_1` = volume of stock solution = ?

`C_2` = concentration of solution to be prepared = 0.52 M

`V_2` = volume of solution to be prepared = 15 L

`15* V_1=0.52* 15`

`V_1=0.52L`

Thus 0.52 L of 15 M
`NH_3(aq)` will be used to prepare this amount of 0.52 M base