Answer:
false
Step-by-step explanation:
In the presence of glucose , the lac operon is in inactive state. In the presence of lactose ,and absence of glucose, the β-galactosides enzyme catalyzes the hydrolysis of lactose, a disaccharide, into glucose and galactose through the breaking of a glycosidic bond, and in turn, operon become active.
lacZ i= β-galactosidase.
LacO = the binding site for the repressor.: Operator
LacI = the gene encoding for the lac repressor protein:Operator