Answer:
a) Maximum potential of the dome = 724.5kV
b) Maximum charge on the dome = 13.9 micro Coulomb
Step-by-step explanation:
Diameter of the dome = 34.5 cm =34.5/100 = 0.345 m
Radius of the dome = Diameter/2 = 0.345/2 = 0.1725 m
Electric field strength, E = 4.20 * 10⁶V/m
a) Maximum potential of the dome, V = E*r
V = 4.20 * 10⁶ * 0.1725
V = 724500 Volts = 724.5kV
b) Maximum charge on the dome
V = kQ/r
Q = Vr/k
Q = (724500 * 0.1725)/(9*10⁹)
Q = 1.39 * 10⁻⁵C
Q = 13.9 micro Coulomb