Answer:
![M = 0.71((U_oNI)/(a))](https://img.qammunity.org/2021/formulas/physics/high-school/i0ewr0qtuu06u5fnzuna63fyf8vdxzeflc.png)
Step-by-step explanation:
The magnitude of the magnetic field at a point P, a distance a/2 from the center of the each coil can be determined as follows;
Let the magnitude be M;
![M=(U_oIa^2)/(2(x^2+a^2)^(3/2))](https://img.qammunity.org/2021/formulas/physics/high-school/y856jpn8cwc66317rqqhf6z6okciwrpnu7.png)
Note that there is a total of 2N turns in the two coils.
So, we have:
![M=(U_oIa^2)/(2(x^2+a^2)^(3/2))*2N](https://img.qammunity.org/2021/formulas/physics/high-school/maood58mnmio2y7m1ztca190qp5dnxmbx4.png)
![M=(U_oNa^2I)/((x^2+a^2)^(3/2))](https://img.qammunity.org/2021/formulas/physics/high-school/ydyir62lvcf0h5f8oljy5o3nhct8bvsxet.png)
where x = distance (d) which is given as a/2; we have:
![M=(U_oNIa^2)/(((a^2)/(4)+a^2)^(3/2))](https://img.qammunity.org/2021/formulas/physics/high-school/a9qjmo3vykjynsabtup61xtnyq7n99wc8r.png)
![M=\frac{U_oNIa^2}{{a^3}((5)/(4))^(3/2)}](https://img.qammunity.org/2021/formulas/physics/high-school/nz5zlywhjjjgve8d06upp6a3v4hglshfzr.png)
![M = ((4)/(5))^(3/2)((U_oNI)/(a))](https://img.qammunity.org/2021/formulas/physics/high-school/z6h5zy2x6wv2pzsdol7nj1aby3maubvdeb.png)
![M = 0.71((U_oNI)/(a))](https://img.qammunity.org/2021/formulas/physics/high-school/i0ewr0qtuu06u5fnzuna63fyf8vdxzeflc.png)