Question

In the following acid-base reactions, identify the spectator ions, if any:

(i) Cesium hydroxide(aq) + nitric acid(aq) =>
(ii) Calcium hydroxide(aq) + acetic acid(aq) =>
a.
(i) Cs+ and NO3-
(ii) no spectator ions
b.
(i) Cs+ and NO3-
(ii) H+ and OH-
c.
(i) no spectator ions
(ii) H+ and OH-
d.
(i) Cs+ and NO3-
(ii) Ca2+ and acetate ion.
e.
(i) no spectator ions
(ii) no spectator ions

Answer 1

In the given acid-base reactions, the spectator ions in cesium hydroxide and nitric acid reaction are Cs+ and NO3-, whereas there are no spectator ions in the reaction between calcium hydroxide and acetic acid. Accordingly, the answer is (i) Cs+ and NO3- for reaction one; and (ii) no spectator ions for reaction two.

Step-by-step explanation:

The student's question concerns the identification of spectator ions in two given acid-base reactions:

(i) Cesium hydroxide(aq) + nitric acid(aq) =>

(ii) Calcium hydroxide(aq) + acetic acid(aq) =>

Spectator ions are ions that exist in the same form on both the reactant and product sides of a chemical equation and do not participate in the reaction. Using the information provided as reference, we can assess both reactions.

For reaction (i), the products of the reaction between cesium hydroxide (CsOH) and nitric acid (HNO3) are water (H2O) and cesium nitrate (CsNO3). Thus, the Cs+ and NO3− ions do not change and are spectator ions.

In reaction (ii), calcium hydroxide (Ca(OH)2) reacts with acetic acid (CH3COOH), forming calcium acetate (Ca(CH3COO)2) and water (H2O). All the ions react and none remain unchanged on both sides; hence, there are no spectator ions.

Therefore, the correct answer is:
(i) Cs+ and NO3−
(ii) no spectator ions

Answer 2

Answer : The correct option is, (d)

(i)
`Cs^+,\text{ and }NO_3^-`

(ii)
`Ca^(2+),\text{ and }CH_3COO^-`

Explanation :

Complete ionic equation : In complete ionic equation, all the substance that are strong electrolyte and present in an aqueous are represented in the form of ions.

Net ionic equation : In the net ionic equations, we are not include the spectator ions in the equations.

Spectator ions : The ions present on reactant and product side which do not participate in a reactions. The same ions present on both the sides.

(i) The balanced molecular equation will be,

`CsOH(aq)+HNO_3(aq)\rightarrow CsNO_3(aq)+H_2O(l)`

The complete ionic equation in separated aqueous solution will be,

`Cs^+(aq)+OH^(-)(aq)+H^(+)(aq)+NO_3^(-)(aq)\rightarrow Cs^+(aq)+NO^(3-)(aq)+H_2O(l)`

In this equation the species
`Cs^+,\text{ and }NO_3^-` are the spectator ions.

(ii) The balanced molecular equation will be,

`Ca(OH)_2(aq)+2CH_3COOH(aq)\rightarrow Ca(CH_3COO)_2(aq)+H_2O(l)`

The complete ionic equation in separated aqueous solution will be,

`Ca^(2+)(aq)+2OH^(-)(aq)+2H^(+)(aq)+2CH_3COO^(-)(aq)\rightarrow Ca^(2+)(aq)+2CH_3COO^(-)(aq)+H_2O(l)`

In this equation the species
`Ca^(2+),\text{ and }CH_3COO^-` are the spectator ions.

Hence, the correct option is, (d)

(i)
`Cs^+,\text{ and }NO_3^-`

(ii)
`Ca^(2+),\text{ and }CH_3COO^-`