Answer:
V₂=28cm³
Explanation:
Way 1
The volume of a cone is
, and h₁ = 30 cm but the base (Ba₁) is 14 cm², so
, where Ba= Base area
if h₂=7cm and Ba₂=12cm² then
![V_(1) =(12cm^(2).7cm)/(3)=28cm^(3)](https://img.qammunity.org/2021/formulas/mathematics/college/k5euynsf0zt7butm05lmbuq7tt58nf2jx2.png)
Way2
If the volume of a cone varies jointly as the height of the cone and the area of the base, then we must find the relationship between the bases and heights of the cones
Ba₁*h₁ = 30cm*14cm² = 420cm³
Ba²*h²= 7cm*12cm² = 84cm³
420/84 = 5; ratio = 5 also
V₂=V₁/5 ⇒ V₂=140cm³/5 = 28cm³