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A disk with a radius of 0.1 m is spinning about its center with a constant angular speed of 10 rad/sec. What are the speed and magnitude of the acceleration of a bug clinging to the rim of the disk?

1) 10 m/s and 10 m/s
2

2) 10 m/s and 0 m/s
2
(Disk spins at constant speed)

3) 0.1 m/s and 1 m/s
2

4) 1 m/s and 10 m/s
2

1 Answer

6 votes

Answer:


v = 1 (m)/(s), a = 10 (m)/(s^(2)) (Option 4)

Step-by-step explanation:

Since the disk is spinning at constant speed, it is noticed that bug is experimenting a speed in tangential direction and acceleration in radial direction. That is to say:


v = \omega \cdot r\\a = \omega^(2) \cdot r


v = (10 (rad)/(s)) \cdot (0.1 m)\\v = 1 (m)/(s)


a = (10 (rad)/(s) )^(2)\cdot(0.1 m)\\a = 10 (m)/(s^(2))

The correct answer is Option 4.

User Ankit Sachan
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