Question

The acceleration of gravity on Earth is approximately 10 m/s2 (more precisely, 9.8 m/s2). If you drop a rock from a tall building, about how fast will it be falling after 3 seconds?

Answer 1

30 m/s

Step-by-step explanation:

Velocity is
`v_(final)=v_(initial)+at` since we know that the initial velocity is 0, and the acceleration is
`9.8 (m)/(s^2) \approx 10 (m)/(s^2)` then we also know that time is 3 seconds it follows that:
`v_(final)=v_(initial)+at=0+10(m)/(s^2)*3s=30(m)/(s)`