Question

The difference in potential between the accelerating plates of a T.V. set is about 30 kV. If the distance between these plates is 1.3 cm, find the magnitude of the uniform electric field in this region.

Answer 1

2.31 * 10^6 V/m

Step-by-step explanation:

The relationship between potential difference and electric field is given as:

V = E * r

=> E = V/r

V = 30kV = 30000V

r = 1.3cm = 0.013m

E = 30000/0.013

E = 2.31 * 10^6 V/m