Answer:
The rate at which the distance between the planes changing is 1500mph
The time the controller have to get one of the airplanes on a different flight path is 0.207hours(12.4minutes)
Explanation:
The two planes are approaching the same point.
Plane1 Velocity = 420miles per hour
Plane2 Velocity = 1440miles per hour.
Since the two planes are flying perpendicular to each other and Velocity is a vector quantity, their resultant Velocity can be calculated with vector addition.
The rate at which the distance between the planes is changing represent the resultant velocity of the two planes.
Therefore,
Vr = sqrt(420^2 + 1440^2)
Vr = 1500mph
Time the controller has to get one of the airplanes on a different flight path is calculated thus:
Time = distance/velocity
Distance that will be travelled by the two airplanes to the converging point is 70 + 240 = 310miles
Therefore, Time = 310/1500 = 0.2066hours = 12.4minutes