Question

The line L passes through the points (5, -5) and (1, 2).
Find the gradient of line L.

Answer 1

hello!

Use the slope formula:-

(the slope is the same as the gradient)

`\sf{\displaystyle(y2-y1)/(x2-x1) }`

`\sf{\displaystyle(2-(-5))/(1-5)}`

`\sf{\displaystyle(2+5)/(-4) }=(7)/(-4) ={\boxed{-(7)/(4) }}\leftarrow\sf{slope~of~line~L}}}`

note:-

Hope everything is clear; if you need any clarification/explanation, kindly let me know, and I will comment and/or edit my answer :)

Answer 2

gradient of L = -7/4

Step-by-step explanation:

`\sf gradient = (y_2-y_1)/(x_2-x_1)`

Insert the following values.

`\rightarrow \sf (2-(-5))/(1-5)`

`\rightarrow \sf (7)/(-4)`

`\rightarrow \sf -(7)/(4)`