Question

A charge of 11.748 nC is uniformly distributed along the x-axis from −2 m to 2 m . What is the electric potential (relative to zero at infinity) of the point at 5 m on the x-axis? The value of the Coulomb constant is 8.98755 × 109 N · m2 /C 2 . Answer in units of V

Answer 1

electric potential = 22.36 volt

Step-by-step explanation:

given data

charge Q = 11.748 nC

distance d = 5 - 2 = 3 m

length = 2 + 2 = 4 m

Coulomb constant = 8.98755 × 109 N·m²/C ²

solution

electric potential is express as

electric potential =
`(Q)/(4\pi \epsilon _o L)`
`ln(1+(L)/(d))` ..............1

electric potential =
`(KQ)/(L) ln(1+(L)/(d))`

put here value

electric potential =
`\frac{8.98755* 10^9* 11.748* 10{-9}}{4} ln(1+(4)/(3))`

electric potential = 22.36 volt