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On a coordinate plane, 3 lines are shown. Line a has points (negative 3, 3) and (3, negative 3). Line b has points (negative 3, negative 2) and (2, 3). Line c is parallel to line b.

If line b is perpendicular to line a, and line c is perpendicular to line a, what is the slope of line c?

User AnandMohanAwasthi
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2 Answers

9 votes
9 votes

Answer:

mc = 1

Explanation:

On a coordinate plane, 3 lines are shown. Line a has points (negative 3, 3) and (3, negative-example-1
User CaptConrado
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2.6k points
25 votes
25 votes

Answer:

slope c =1

Explanation:

slope for line (y2-y1)/(x2-x1)

slope of line a = (-3-3)/(3-(-3))

slope of line a = -6/6 = -1

if line c is perpendicular to line a, so relationship for slops are

(slope a) *(slope c)= -1

(-1)*(slope c) = -1

slope c =1

User Salexch
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2.6k points