Step-by-step explanation:
(a) 0.036 M HCl
[HCl] = 0.036 M
As HCl is a strong acid, it will completely dissociate and produce H+ ions.
[ H+] = M
pH = −log [ H+]
pH = −log[0.036]
pH = −(−1.444)
pH = 1.44
(b) 0.17 M KOH
pH + pOH = 14
pH = −log10[H+], and pOH = 14−pH
pH = 14 − pOH
pH = 14 − (−log10(0.17))
pH = 14 − (0.77) = 13.23
(c) 0.19 M Ba(OH)2
[H+] [OH−] = 1.0×10−14M
[OH−] = 2 * 0.19 = 0.38M
[H+] = 2.63 ×10−14M
pH = −log10([H+])
pH = −log10(2.63 ×10−14) = 13.58.