Question

Find the equation of the line that passes through the point (7,-3) and is perpendicular to the line y=1/6x-2

Answer 1

y= -6x + 39

Explanation:

y = 1/6x - 2

to find the equation that is perpendicular to it, there gradients timesed together equal -1

so 1/6 × ? = -1

? = -6

so the start of the equation is,

y = -6x + c

now we need to sub in the coordinates (7,-3) to find the rest of the equation

-3 = -6(7) + c

-3 = -42 + c

39 = c

so the equation is...

y= -6x + 39