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Assume you stand between two loudspeakers that are excited by the same oscillator emitting a1150 Hz sound frequency. You stand at a distance of 4 m from one of the loudspeakers.I - What is the wavelength of the sound waves? Assume thatcs= 343 m/s. g

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Answer:


\lambda = 0.299\,m

Step-by-step explanation:

The wavelength of a wave is given by this expression:


v_(air) = \lambda\cdot f_(osc)


\lambda = (v_(air))/(f_(osc))


\lambda = (343\,(m)/(s) )/(1150\,Hz)


\lambda = 0.299\,m

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