Question

The time of a call to a technical support line is uniformly distributed between 2 and 10 minutes. What are the mean and variance of this distribution?

Answer 1

Mean is 6

Variance is 5.33

Explanation:

An uniform probability is a case of probability in which each outcome is equally as likely.

For this situation, we have a lower limit of the distribution that we call a and an upper limit that we call b.

The mean of the distribution is:

`M = (a + b)/(2)`

The variance of the distribution is:

`V = ((b-a)^(2))/(12)`

Uniformly distributed between 2 and 10 minutes.

This means that
`a = 2, b = 10`

Mean

`M = (2 + 10)/(2) = 6`

`V = ((10 - 2)^(2))/(12) = 5.33`