If f(1)=2 and f(n) = f(n-1)^2+4 then what is the value of f(3)?

asked Aug 14, 2023 58.9k views

21 votes

by Jinyu

7.6k points

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3 votes

Answer:

f(3) = 68

Explanation:

Given:

$\sf f(1)=2$

$\sf f(n) = f(n-1)^2+4$

$\sf \implies f(2) = f(1)^2+4$

$\sf \implies f(2) = 2^2+4=8$

$\sf \implies f(3) = f(2)^2+4$

$\sf \implies f(3) = 8^2+4=68$

Remmyabhavan answered Aug 18, 2023

8.2k points

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