Question

Nitrogen at an initial state of 300 K,150 kPa and 0.2 m3is compressed slowly in an isothermal process to a final pressure of 800 kPa. Determine the work done to the nitrogen and the amount of heat transfer during this process.

Answer 1

-50.22kJ

Step-by-step explanation:

Given:

Initial state Temperature =300k

Pressure 1= 150kPa

Pressure 2 = 800kPa

Volume 1 = 0.2m^3

Work done = Pressure 1 × Volume 1 × (inverse of pressure 1 ÷ pressure 2)

= 150kPa × 0.2m^3 × (inv 150 kPa ÷800 kPa)

= - 50.22kJ