Question

A crate weighing 250 N is pulled up a 20° incline by a rope with a tension of 200 N. If the crate moves 5 m up the incline, what was the work done on the crate by the rope? (T remains constant throughout)

Answer 1

The work done on the crate by the rope is approximately 939.7 J.

Step-by-step explanation:

To calculate the work done on the crate by the rope, we can use the formula:

Work = Force x Distance x Cosine(theta)

In this case, the force is 200 N, the distance is 5 m, and the angle theta is 20 degrees. Plugging these values into the formula:

Work = 200 N x 5 m x Cosine(20°)

Simplifying the expression:

Work = 200 N x 5 m x 0.9397

Work ≈ 939.7 J