Answer: P(x>3) = 0.7983
Step-by-step explanation: the average number of goals scored by a team every match is independent on each other and it is occurring at a fixed rate hence, u = 1.1
The probability mass function that defines a possion distribution is given as
P(x=r) = e^-u × u^x/ x!
If the team scores and average of 1.1 goals in one game, then in the next five game they will score an average of (1.1×5 = 5.5)
So therefore, for the next five games, u = 5.5
The question is to find the probability of the team scoring more than 3 goals in the next 5 games, that's
P(x>3).
P(x>3) = 1 - P(x≤2)
The value of P(x≤2) can be gotten using a cumulative possion distribution table with the fact that u = 5.5 and x = 2.
By checking the table, we have that P(x≤2) = 0.2017
P(x>3) = 1 - 0.2017
P(x>3) = 0.7983