Answer:
The answer is 0.06
Step-by-step explanation:
CH₃COOH → Acetic acid
We determine the molar mass of acetic, which represents the mass of acetic contained in 1 mol
12g/mol . 2 + 1g/mol .4 + 16g/mol . 2 = 60 g/mol
We determine the moles for 3.6 g of CH₃COOH
3.6 g . 1mol / 60g = 0.06 moles