Question

A barium hydroxide solution is prepared by dissolving 1.90 g of Ba ( OH ) 2 in water to make 71.1 mL of solution. What is the concentration of the solution in units of molarity?

Answer 1

The molarity of this solution is 0.156 M

Step-by-step explanation:

Step 1: Data given

Mass of Ba(OH)2 = 1.90 grams

Molar mass Ba(OH)2 = 171.34 g/mol

Volume of the solution = 71.1 mL = 0.0711 L

Step 2: Calculate moles Ba(OH)2

Moles Ba(OH)2 = mass Ba(OH)2 / molar mass Ba(OH)2

Moles Ba(OH)2 = 1.90 grams / 171.34 g/mol

Moles Ba(OH)2 = 0.0111 moles

Step 3: Calculate molarity

Molarity solutin = moles Ba(OH)2 / volume solution

Molarity solution = 0.0111 moles / 0.0711 L

Molarity solution = 0.156 M

The molarity of this solution is 0.156 M