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transformer has 26 turns on the primary coil and 720 turns on the secondary coil. If this transformer is to produce an output of 4100 V with a 16-mA current, what input current and voltage are needed

User Gosha A
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1 Answer

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Corrected Question:

A step-up transformer has 26 turns on the primary coil and 720 turns on the secondary coil. If this transformer is to produce an output of 4100 V with a 16-mA current, what input current and voltage are needed?

Answer:

The input current and voltage needed are 443 mA and 148 V respectively.

Step-by-step explanation:

In a step-up transformer, the relationship between the number of turns in its primary coil (
N_(p)), the number of turns in its secondary coil (
N_(s)), the input voltage (
V_(p)), the output voltage (
V_(s)), the input current (
I_(p)), and the output current (
I_(s)) is given by;


(N_(s) )/(N_(p) ) =
(V_(s) )/(V_(p) ) =
(I_(p) )/(I_(s) )

This implies that;


(N_(s) )/(N_(p) ) =
(V_(s) )/(V_(p) ) ---------------------(i)


(N_(s) )/(N_(p) ) =
(I_(p) )/(I_(s) ) ---------------------(ii)

From the question;


N_(p) = 26 turns


N_(s) = 720 turns


V_(s) = 4100V


I_(s) = 16mA = 16 x 10⁻³A

(a) Substitute these values into equation (ii) as follows;


(720)/(26) =
(I_(p) )/(16*10^(-3))

Solve for
I_(p);


I_(p) = 720 x 16 x 10⁻³ / 26


I_(p) = 443 x 10⁻³


I_(p) = 443 mA

Therefore the input current needed is 443mA

(b) Also, substitute those values into equation (i) as follows;


(720)/(26) =
(4100 )/(V_(p) )

Solve for
V_(p);


V_(p) = 4100 x 26 / 720


V_(p) = 148 V

Therefore, the input current needed is 148 V

User Shamarie
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