Question

You need a 40% alcohol solution. On hand, you have a 100 mL of a 25% alcohol mixture. You also have 65% alcohol mixture. How much of the 65% mixture will you need to add to obtain the desired solution

Answer 1

Answer: 60 ml of the 65% mixture will you need to add to obtain the desired solution.

Step-by-step explanation:

According to the dilution law,

`C_1V_1+C_2V_2=C_3V_3`

where,

= concentration of given alcohol solution = 25 %

`V_1` = volume of given alcohol solution = 100 ml

`C_2` = concentration of another alcohol solution=65 %

`V_2` = volume of another acid solution= x ml

`C_3` = concentration of resulting alcohol solution = 40 %

`V_3` = volume of resulting acid solution = (100+x)

`25* 100+65* x=40* (100+x)`

`x=60ml`

Thus 60 ml of the 65% mixture will you need to add to obtain the desired solution.