Question

The height (in meters) of a projectile shot vertically upward from a point 2 m above ground level with an initial velocity of 23.5 m/s is h = 2 + 23.5t − 4.9t2 after t seconds. (Round your answers to two decimal places.) (a) Find the velocity after 2 s and after 4 s. v(2) = m/s v(4) = m/s

Answer 1

a)
`v(2) = 3.9\,(m)/(s)`, b)
`v(4) = -15.7\,(m)/(s)`

Step-by-step explanation:

a) The equation for vertical velocity is obtained by deriving the function with respect to time:

`v(t) = 23.5 -9.8\cdot t`

The velocities at given instants are, respectivelly:

`v(2) = 3.9\,(m)/(s)`

`v(4) = -15.7\,(m)/(s)`