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A heavy turntable, used for rotating large objects, is a solid cylindrical wheel that can rotate about its central axle with negligible friction. The radius of the wheel is 0.330 m. A constant tangential force of 300 N applied to its edge causes the wheel to have an angular acceleration of 0.876 rad/s2.

(a)
What is the moment of inertia of the wheel (in kg · m2)?

_____ kg · m2

(b)What is the mass (in kg) of the wheel?

_________ kg

(c)The wheel starts from rest and the tangential force remains constant over a time period of 6.00 s. What is the angular speed (in rad/s) of the wheel at the end of this time period?

________ rad/s

User Soulsabr
by
4.7k points

1 Answer

4 votes

Answer:

a)
I = 113.014\,kg\cdot m^(2), b)
m = 2075.556\,kg

Step-by-step explanation:

a) The turntable has the following physical model by using Newton's laws:


F \cdot R = I \cdot \alpha

The moment of inertia is:


I = (F\cdot R)/(\alpha)


I = ((300\,N)\cdot(0.33\,m))/(0.876\,(rad)/(s^(2)) )


I = 113.014\,kg\cdot m^(2)

b) The moment of inertia for a solid cylinder:


I = (1)/(2)\cdot m \cdot R^(2)

The mass of the turntable is:


m = (2 \cdot I)/(R^(2))


m = ((2)\cdot (113.014\,kg\cdot m^(2)))/((0.33\,m)^(2))


m = 2075.556\,kg

User Manoj Singh
by
5.0k points