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A man can swim at 4 ft/s in still water. He wishes to cross tje 40-ft wide river to point B, 30 ft downstream. If the river flows with a velocity of 2 ft/s, determine the speed of the man and the time needed to make the crossing. Note While in the water he must not direct himself toward point B to reach the point.

User Ericmp
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1 Answer

3 votes

Answer:


v \approx 4.472\,(ft)/(s),
t = 10\,s

Step-by-step explanation:

Since man and river report constant speeds and velocities are mutually perpendicullar, the absolute speed of the man is calculated by the Pythagorean Theorem:


v = \sqrt{(4\,(ft)/(s) )^(2)+(2\,(ft)/(s) )^(2)}


v \approx 4.472\,(ft)/(s)

The required time to make the crossing is:


t = (40\,ft)/(4\,(ft)/(s) )


t = 10\,s

User Nikolay K
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