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Need help with this chemistry stoichiometry worksheet any help is appreciated with work shown!

Need help with this chemistry stoichiometry worksheet any help is appreciated with-example-1

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Answer:

I suggest you study. These can burn up time, so balance the stoichiometry,

Between Oxygen and Propane to yield carbon dioxide.

Aluminum is tricky; Al2O3 is the best choice, especially for the shorter time and what you can learn

Step-by-step explanation:

User John Oxley
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1) The mass of iron III oxide is 3.92 g and the mass of water is 1.32 g

2) The mass of the Mg is 19.44 g

3) The mass of calcium phosphate is 109 g

What is stoichiometry?

1) The equation is;


2Fe(OH)_3 - > Fe_2O_3 + 3H_2O

Number of moles of iron III hydroxide

Moles = Mass/Molar mass

= 5.25 g/107 g/mol

= 0.049 moles

2 moles of iron III hydroxide produces 1 mole of iron III oxide

0.049 moles of iron III hydroxide produces 0.049 moles * 1 mole/2 moles

=0.0245 moles

Mass iron III oxide = 0.0245 moles * 160 g/mol

= 3.92 g

2 moles of of iron III hydroxide produces 3 moles of water

0.049 moles of iron III hydroxide produces 0.049 moles * 3 moles/ 2 moles

= 0.0735 moles

Mass of water = 0.0735 moles * 18 g/mol

= 1.32 g

2) Moles of magnesium fluoride = 50 g/62 g/mol

= 0.81 moles


Mg + F_2 -- > MgF_2

1 mole of Mg produces 1 mole of magnesium fluoride

x moles of Mg produces 0.81 moles of magnesium fluoride

x = 1 * 0.81/1

= 0.81 moles of Mg

Mass of the Mg = 0.81 moles * 24 g/mol

= 19.44 g

3)
3CaO + P_2O_5 --- > Ca_3(PO_4)_2

Moles of calcium oxide = 100 g/56 g/mol

= 1.79 moles

Moles of phosphorus pentaoxide = 100 g/284 g/mol

= 0.35 moles

If 3 moles of calcium oxide reacts with 1 mole of phosphorus pentaoxide

1.79 moles of calcium oxide reacts with 1.79 * 1/3

= 0.596 moles

Thus phosphorus pentaoxide is the limiting reactant

1 mole of phosphorus pentaoxide produces 1 mole of calcium phosphate

0.35 moles of phosphorus pentaoxide produces 0.35 moles of calcium phosphate

Mass of calcium phosphate produced = 0.35 moles * 310 g/mol

= 109 g

User Ksm
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