Question

Both portions of the rod ABC are made of an aluminum for whichE = 70 GPa. Knowing that the magnitude of P is 4 kN, determine(a) the value of Q so that the deflection at A is zero, (b) the correspondingdeflection of B.0.4 m0.5 m

Answer 1

Step-by-step explanation:

Δ
`L_(BC)` = Δ
`L_(AB)`

`((Q - 4000)(0.5))/(3.14* 0.03 *0.03 *70*10^(9) )` (1)

=
`(4000*0.4)/(3.14*0.01*0.01*70*10^(9) )`

Q = 32,800 N

now put this value in equation 1.

Deflection of B =
`((32800-4000)(0.5))/(3.14*0.03*0.03*70*10^(9) )`

= 0.0728 mm