Question

A volley ball is hit directly toward the ceiling in a gymnasium with a ceiling height of L 0 m. If the initial vertical velocity is 13 m/s and the release height is 1.8 m will the ball hit the ceiling?

Answer 1

Complete Question:

A volley ball is hit directly toward the ceiling in a gymnasium with a ceiling height of 10 m. If the initial vertical velocity is 13 m/s and the release height is 1.8 m will the ball hit the ceiling?

Answer:

The ball will hit the ceiling

Step-by-step explanation:

Given;

Initial vertical Velocity U = 13 m/s

Height of the ceiling = 10 m

Released height of the volley ball = 1.8 m

Height traveled by the volley ball, is calculated as follows;

`V^2 =U^2 -2gH`

where;

V is final vertical velocity

`2gH =U^2\\\\H = (U^2)/(2g) = ((13)^2)/(2(9.8)) = 8.62 m`

Remember this ball was released from 1.8 m height and it traveled 8.62 m.

Total distance traveled = 1.8 + 8.62 = 10.42 m

Therefore, the ball will hit the ceiling