H(x)= {1/x-5 , x=0 {-(x-4)^2, x=7 { 3x-2, x~0,7 h(6)

Aunlead asked Apr 24, 2023

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19 votes

H(x)= {1/x-5 , x=0
{-(x-4)^2, x=7
{ 3x-2, x~0,7
h(6)

Aunlead asked Apr 24, 2023

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16 votes

Answer:

Explanation:

h(x)=3x-2 in (0,7)

h(6)=3(6)-2=18-2=16

Mataniko answered Apr 29, 2023

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