Question

A chemist adds of a sodium carbonate solution to a reaction flask. Calculate the mass in grams of sodium carbonate the chemist has added to the flask. Be sure your answer has the correct number of significant digits.

Answer 1

The question is incomplete, here is the complete question:

A chemist adds 180.0 mL of a 1.42 M sodium carbonate solution to a reaction flask. Calculate the mass in grams of sodium carbonate the chemist has added to the flask. Be sure your answer has the correct number of significant digits.

Answer: The mass of sodium carbonate that must be added are 40.9 grams

Step-by-step explanation:

To calculate the mass of solute, we use the equation used to calculate the molarity of solution:

`\text{Molarity of the solution}=\frac{\text{Mass of solute}* 1000}{\text{Molar mass of solute}* \text{Volume of solution (in mL)}}`

Molar mass of sodium carbonate = 106 g/mol

Molarity of solution = 1.42 M

Volume of solution = 180.0 mL

Putting values in above equation, we get:

`1.42mol/L=\frac{\text{Mass of sodium carbonate}* 1000}{160g/mol* 180}\\\\\text{Mass of sodium carbonate}=(160* 1.42* 180)/(1000)=40.9g`

Hence, the mass of sodium carbonate that must be added are 40.9 grams