Question

A pump contains 1.5 L of air at 175 kPa. You draw back on the piston of the pump, expanding the volume until the pressure reads 45 kPa. What is the new volume of air in the pump?

Answer 1

`\large \boxed{\text{86.8 L}}`

Step-by-step explanation:

The temperature and amount of gas are constant, so we can use Boyle’s Law.

`p_(1)V_(1) = p_(2)V_(2)`

Data:

`\begin{array}{rclrcl}p_(1)& =& \text{0.579 atm}\qquad & V_(1) &= & \text{150 L} \\p_(2)& =& \text{1.00 atm}\qquad & V_(2) &= & ?\\\end{array}`

Calculations:

`\begin{array}{rcl}0.579 * 150 & =& 1.00V_(2)\\86.85 & = & 1.00V_(2)\\V_(2) & = &(86.85)/(1.00)\\\\& = &\textbf{86.8}\\\end{array}\\\text{The new volume of the gas is } \large \boxed{\textbf{86.8 L}}`