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H(x)= {1/x-5 , x=0 {-(x-4)^2, x=7 { 3x-2, x~0,7 h(6)
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H(x)= {1/x-5 , x=0
{-(x-4)^2, x=7
{ 3x-2, x~0,7
h(6)

User Dan Wagner
by
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1 Answer

3 votes

Answer:

16

Explanation:

h(x)=3x-2 in (0,7)

h(6)=3(6)-2=18-2=16

User Larsdk
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3.9k points
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