Question

At a recent audition school play, 1 out of 3 students who auditioned were asked to come to a second audition . After the second audition ,75% of those asked to the second audition were offered parts. If 18 students were offered parts , how many students were offered to the first audition

Answer 1

The total students appearing in first audition = 72

Explanation:

As given in the question:

1 out of 3 students were asked to come for second audition.

Let us assume the TOTAL STUDENT who came to first audition = m

So,
`((1)/(3)) m` appeared for the SECOND ROUND.

Now, 75% of students appearing in second audition were offered parts.

Calculating 75% of
`((1)/(3)) m`

`(75)/(100) *(1)/(3) m = 0.25 m`

Also, as said 18 students were offered parts.

⇒ 0. 25 m = 18

Now, solving for m, we get:

m = 18/0.25 = 72

or, m = 72

Hence, the total students appearing in first audition = 72