Answer:
The electric potential is 15.23 V
Step-by-step explanation:
Given;
charge Q = 8.473 nC = 8.473 x 10⁻⁹ C
position of the charge, r = 5 m
Coulomb constant is 8.98755 × 10⁹ N·m² /C²
Electric potential is given as;

Therefore, a charge of 8.473 nC uniformly distributed along the x-axis from −1 m to 1 m, the electric potential (relative to zero at infinity) of the point at 5 m on the same axis is 15.23 V.