Question

How many moles of aluminum hydroxide are needed to react with 25 grams of sulfuric acid?

Answer 1

0.16 moles of Aluminum hydroxide are needed to react with 25 grams of sulfuric acid.

Step-by-step explanation:

In order to find the number of moles we first need to write down the balanced equation as,

`3 H_(2) S O_(4)+2 A l(O H)_(3) \stackrel{\text { yiek }}{\longrightarrow} \mathrm{Al}_(2)\left(\mathrm{SO}_(4)\right)_(3)+6 \mathrm{H}_(2) \mathrm{O}`

Now as mentioned above,For 3 moles of sulfuric acid , we need 2 moles of Aluminum hydroxide to balance the equation,

Thus we can balance it as,

`\begin{aligned}25 \mathrm{g} \text { of } \mathrm{H}_(2) \mathrm{SO}_(4) & * \frac{1 \mathrm{mol} \text { of } \mathrm{H}_(2) \mathrm{SO}_(4)}{98.079 \frac{\mathrm{g}}{\mathrm{mol}}} * \frac{2 \mathrm{mol} \mathrm{Al}(\mathrm{OH})_(3)}{3 \mathrm{mol} \mathrm{H}_(2) \mathrm{SO}_(4)} \\\\&=0.16 \mathrm{mol} \mathrm{Al}(\mathrm{OH})_(3)\end{aligned}`

Thus it is now clearly known that 0.16 moles of Aluminum hydroxide are needed to react with 25 grams of sulfuric acid.