Question

A line is perpendicular to y = 3x - 8

and intersects the point (2,2).
What is the equation of this
perpendicular line?

Answer 1

y=-1/3x+8/3

Explanation:

y=3x-8 k1=3

k1*k2=-1

3*k2=-1

k2=-1/3

A(2,2) x1=2, y1 =2

y-y1 =k2(x-x1)

y-2=-1/3(x-2)

y-2=-1/3x+2/3

y=-1/3x+2/3+2

y=-1/3x+2/3+6/3

y=-1/3x+8/3