Question

A wire with current I = 15 A flows at an angle of 30 degrees to the direction of a uniform magnetic field of 0.9 T. What is the magnitude of the force exerted on a 10 m length of wire? (in units of N)

Answer 1

67.5

Step-by-step explanation:

`F= BILsin\theta` where F is the magnitude of the force, B is the magnetic field, I is current,
`\theta` is the angle of inclination, L is the length of the wire.

Substituting 0.9 T for magnetic field B, 10 m for length, 15 A for current I and 30 degrees for
`\theta` then

`F=0.9* 15* 10* sin 30^(\circ)=67.5`