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A 111.6 g sample of iron was heated from 0°C to 20°C. It absorbed 1004 J of energy. What is the specific heat capacity of iron? A 0.00578 J/g°C B 0.45 J/g°C C 2.20 J/g°C D 4.18 J/g°C

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Answer:

b.


0.45J/g\textdegree C

Step-by-step explanation:

Specific heat capacity is the amount of heat required to raise one gram of substance by one degree celcius.

It's calculated by the formula:
s=(q)/(m\bigtriangleup T), where q=heat and m= mass


\bigtriangleup T=20-0=20\textdegree C\\q=1004J\\m=111.6g

Therefore:


s=(1004J)/(111.6g*20\textdegree C)\\=0.45J/g\textdegree C

Hence the iron's specific heat capacity is
0.45J/g\textdegree C

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