Question

A 111.6 g sample of iron was heated from 0°C to 20°C. It absorbed 1004 J of energy. What is the specific heat capacity of iron? A 0.00578 J/g°C B 0.45 J/g°C C 2.20 J/g°C D 4.18 J/g°C

Answer 1

b.

`0.45J/g\textdegree C`

Step-by-step explanation:

Specific heat capacity is the amount of heat required to raise one gram of substance by one degree celcius.

It's calculated by the formula:
`s=(q)/(m\bigtriangleup T)`, where q=heat and m= mass

`\bigtriangleup T=20-0=20\textdegree C\\q=1004J\\m=111.6g`

Therefore:

`s=(1004J)/(111.6g*20\textdegree C)\\=0.45J/g\textdegree C`

Hence the iron's specific heat capacity is
`0.45J/g\textdegree C`