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2 votes
Factor Completely.

12v3 – 32v2 + 6v – 16


A. 2(2v2 – 1)(3v – 8)


B. 2(2v2 + 1)(3v – 8)


C. (2v2 + 1)(3v – 8)

User Astolfo
by
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1 Answer

6 votes

Answer:

The answer to your question is letter B

Explanation:

Data

12v³ - 32v² + 6v - 16

- Factor the first 2 terms by common factor

12v³ - 32v² = 4v² (3v - 8)

- Factor the last two terms by common factor

6v - 16 = 2(3v - 8)

- Write the previous results

4v²(3v - 8) + 2(3v - 8)

- Factor again by common factor

(3v - 8) (4v² + 2)

- Factor by common term

2(3v - 8)(2v² + 1)

User Ustmaestro
by
4.8k points