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Circle E, and are diameters. Angle BCA measures 53°.

Circle E is shown. Line segments A C and B D are diameters. Lines are drawn to connect points B and C and points A and D. Angle B C A is 53 degrees.

What is the measure of arc AD?

53°
74°
106°
180°

User Jannette
by
3.8k points

2 Answers

6 votes

Answer:

The answer is B on Edge 2020`

Explanation:

I did the exam

User Travel
by
4.5k points
3 votes

Answer:

74°

Explanation:

see the attached figure to better understand the problem

we know that

Triangle EBC is an isosceles triangle (because has two equal sides EB=EC)

so


m\angle BCA=m\angle BCE=m\angle EBC=53^o

Find the measure of angle BEC

Remember that the sum of the interior angles in any triangle must be equal to 180 degrees

so


m\angle BCE+m\angle EBC+m\angle BEC=180^o

substitute the given values


53^o+53^o+m\angle BEC=180^o


m\angle BEC=180^o-106^o=74^o

Find the measure of angle AED

we know that


m\angle AED=m\angle BEC ----> by vertical angles

so


m\angle AED=74^o

Find the measure of arc AD

we know that


m\ arc\ AD=m\angle AED -----> by central angle

therefore


m\ arc\ AD=74^o

Circle E, and are diameters. Angle BCA measures 53°. Circle E is shown. Line segments-example-1
User Oleksiy
by
4.6k points