Question

Two particles, one with charge − 7.97 μC and one with charge 3.55 μC, are 6.59 cm apart. What is the magnitude of the force that one particle exerts on the other?

Answer 1

58.6 N

Step-by-step explanation:

We are given that

`q_1=-7.97\mu C=-7.97* 10^(-6) C`

`q_2=3.55\mu C=3.55* 10^(-6) C`

Using
`1\mu C=10^(-6) C`

`r=6.59 cm=6.59* 10^(-2) m`

`1 cm=10^(-2) m`

The magnitude of force that one particle exerts on the other

`F=(kq_1q_2)/(r^2)`

Where
`k=9* 10^9`

Substitute the values

`F=(9* 10^9* 7.97* 10^(-6)* 3.55* 10^(-6))/((6.59* 10^(-2))^2)`

F=58.6 N