Question

HELP! PLEASE! Jackson is building a small rectangular basketball section in his backyard. The length of the section will be 1.25 times the width of the section.

Part A
Create an equation to represent the area of the basketball section, A, in terms of the width, w.
Part B
Jackson decides to make the area of the basketball section 245 square feet. What are the dimensions, in feet, of the basketball section?
SHOW ALL WORK PLEASE

Answer 1

Part A)
`A=1.25W^2`

Part B) Length: 17.5 feet and Width: 14 feet

Explanation:

Part A) Create an equation to represent the area of the basketball section A, in terms of the width W.

Let

L ----> the length of the rectangular basketball section

W ---> the width of the rectangular basketball section

we know that

The area of the rectangular basketball section is equal to

`A=LW` ----> equation A

The length of the section will be 1.25 times the width of the section

so

`L=1.25W` ----> equation B

substitute equation B in equation A

`A=(1.25W)W\\A=1.25W^2`

Part B) Jackson decides to make the area of the basketball section 245 square feet. What are the dimensions, in feet, of the basketball section?

we have

`A=1.25W^2\\A=245\ ft^2`

so

`245=1.25W^2`

solve for W

`W^2=245/1.25\\W^2=196\\W=14\ ft`

Find the value of L

substitute the value of W in the equation B

`L=1.25(14)=17.5\ ft`

therefore

The dimensions are :

Length: 17.5 feet

Width: 14 feet