Question

The pKa of an acid (one dissociable hydrogen) is -5.7. To the nearest ones, what is the Ka of this acid? Please note that we should use scientific notation and fewer significant figures, but Canvas is not configured to use scientific notation.

Answer 1

The value of dissociation constant of an acid
`5.0* 10^(5)`.

Step-by-step explanation:

The
`pK_a` of an acid = -5.7

The dissociation constant of the reaction =
`K_a`

The relation between
`pK_a` and
`K_a` is given by ;

`pK_a=-\log[K_a]`

`-5.7=-\log[K_a]`

`K_a=10^(-(-5.7))=5.012* 10^(5)\approx 5.0* 10^(5)`

The value of dissociation constant of an acid
`5.0* 10^(5)`.